Wednesday, October 3, 2012

A Quick 4E Game Algorithm

Four players and three encounters, three hours.
For each additional player, add 1/2 hour to the final total (e.g. six players would make it 4.5 hours)


  1. Three counters? Or three encounters?

    1. Thanks, I made the post pretty late last night after Mrs. Q pointed this out to me. We're gaming tomorrow with the full complement (six), rather than the skeleton-crew (three plus a substitute) we had last session. It really does make a difference.

      I didn't mention one other, obvious factor--the number of different monsters in each encounter. One controller and four identical brutes will go much quicker than one controller, two skirmishers, one brute and four minions.

  2. 3 + 1/2 + 1/2 = 4, not 4 1/2...?


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